fork download
  1. #include<bits/stdc++.h>
  2. using namespace std;
  3. #define endl '\n'
  4. #define int long long
  5. const int MOD = pow(10,9)+7;
  6. const int MOD2 = 998244353;
  7. const int INF = LLONG_MAX/2;
  8.  
  9. int primes[1000000];
  10.  
  11. void seive(){
  12. fill(primes, primes + 1000000, 1);
  13. primes[0] = primes[1] = 0;
  14. for(int i = 2 ; i*i < 1000000 ; i++){
  15. if(primes[i]){
  16. for(int j = i*i ; j < 1000000 ; j += i){
  17. primes[j] = 0;
  18. }
  19. }
  20. }
  21. for(int i = 1 ; i < 1000000 ; i++){
  22. primes[i] += primes[i-1];
  23. }
  24. }
  25. int factorial(int n){
  26. if(n==0){
  27. return 1;
  28. }
  29. return (n*(factorial(n-1)))%MOD;
  30. }
  31. bool isPrime(int n){
  32. if(n <= 1) return false;
  33. for(int i = 2 ; i*i <= n ; i++){
  34. if(n % i == 0) return false;
  35. }
  36. return true;
  37. }
  38.  
  39. int power(int a, int b){
  40. if(b == 0) return 1;
  41. a %= MOD;
  42. int value = power(a, b / 2);
  43. if(b % 2 == 0){
  44. return (value * value) % MOD;
  45. } else {
  46. return ((value * value) % MOD * (a % MOD)) % MOD;
  47. }
  48. }
  49.  
  50. int gcd(int a, int b){
  51. if(a == 0) return b;
  52. return gcd(b % a, a);
  53. }
  54. void solve() {
  55. int n,target;
  56. cin>>n>>target;
  57. int nums[n];
  58. for(int i = 0 ; i<n ; i++){
  59. cin>>nums[i];
  60. }
  61. int p = -1,q=-1;
  62. if(n==0){
  63. cout<<p<<" "<<q<<endl;
  64. }
  65. else{
  66. int l = 0 , r = n-1;
  67. while(l<=r){
  68. int mid = l+((r-l)/2);
  69. if(nums[mid]<target){
  70. l = mid+1;
  71. }
  72. else{
  73. r = mid-1;
  74. }
  75. }
  76. if(l<n && nums[l]==target){
  77. p = l;
  78. }
  79. l = 0,r=n-1;
  80. while(l<=r){
  81. int mid = l+((r-l)/2);
  82. if(nums[mid]<=target){
  83. l = mid+1;
  84. }
  85. else{
  86. r = mid-1;
  87. }
  88. }
  89. if(r>=0 && r<n && nums[r]==target){
  90. q = r;
  91. }
  92. cout<<p<<" "<<q<<endl;
  93. }
  94. }
  95.  
  96. signed main(){
  97. ios::sync_with_stdio(false); cin.tie(NULL);
  98. int t;
  99. cin >> t;
  100. while(t--){
  101. solve();
  102. }
  103. return 0;
  104. }
  105.  
  106.  
Success #stdin #stdout 0.01s 5320KB
stdin
3
6 8
5 7 7 8 8 10
6 6
5 7 7 8 8 10
0 0
stdout
3 4
-1 -1
-1 -1