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  1. #include<bits/stdc++.h>
  2. using namespace std;
  3. #define endl '\n'
  4. #define int long long
  5. const int MOD = pow(10,9)+7;
  6. const int MOD2 = 998244353;
  7. const int INF = LLONG_MAX/2;
  8.  
  9. int primes[1000000];
  10.  
  11. void seive(){
  12.     fill(primes, primes + 1000000, 1);
  13.     primes[0] = primes[1] = 0;
  14.     for(int i = 2 ; i*i < 1000000 ; i++){
  15.         if(primes[i]){
  16.             for(int j = i*i ; j < 1000000 ; j += i){
  17.                 primes[j] = 0;
  18.             }
  19.         }
  20.     }
  21.     for(int i = 1 ; i < 1000000 ; i++){
  22.         primes[i] += primes[i-1];
  23.     }
  24. }
  25. int factorial(int n){
  26.     if(n==0){
  27.         return 1;
  28.     }
  29.     return (n*(factorial(n-1)))%MOD;
  30. }
  31. bool isPrime(int n){
  32.     if(n <= 1) return false;
  33.     for(int i = 2 ; i*i <= n ; i++){
  34.         if(n % i == 0) return false;
  35.     }
  36.     return true;
  37. }
  38.  
  39. int power(int a, int b){
  40.     if(b == 0) return 1;
  41.     a %= MOD;
  42.     int value = power(a, b / 2);
  43.     if(b % 2 == 0){
  44.         return (value * value) % MOD;
  45.     } else {
  46.         return ((value * value) % MOD * (a % MOD)) % MOD;
  47.     }
  48. }
  49.  
  50. int gcd(int a, int b){
  51.     if(a == 0) return b;
  52.     return gcd(b % a, a);
  53. }
  54. void solve() {
  55.     int n1,m1;
  56.     cin>>n1>>m1;
  57.     int A[n1][n1];
  58.     for(int i = 0 ; i<m1 ; i++){
  59.         int a,b;
  60.         cin>>a>>b;
  61.         A[a][b] = 1;
  62.         A[b][a] = 1;
  63.     }
  64.     for(int i = 0 ; i<n1 ; i++){
  65.         int cnt = 0;
  66.         for(int j = 0 ; j<n1 ; j++){
  67.              if(A[i][j]==1){
  68.                 cnt++;
  69.              }
  70.         }
  71.         cout<<"Node "<<i<<" has "<<cnt<<" direct edges"<<endl;
  72.     }
  73. }
  74.  
  75. signed main(){
  76.     ios::sync_with_stdio(false); cin.tie(NULL);
  77.     //int t;
  78.     //cin >> t;
  79.     //while(t--){
  80.         solve();
  81.     //}
  82.     return 0;
  83. }
  84.  
  85.  
Success #stdin #stdout 0.01s 5328KB
comments (?)
stdin
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5 4 
0 1 
1 2 
2 3 
2 4
stdout
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Node 0 has 1 direct edges
Node 1 has 2 direct edges
Node 2 has 3 direct edges
Node 3 has 1 direct edges
Node 4 has 1 direct edges
https://ideone.com/hvrAIn
language:
C++14 (gcc 8.3)
created:
1 day ago
visibility:
public

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