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  1. #include <stdio.h>
  2.  
  3. int main(){
  4.     int n = 1;
  5.     int t = 0;
  6.  
  7.     while (n <= 100){
  8.         if (n % 3 != 0 && n % 5 != 0){
  9.             t = t + n;
  10.         }
  11.         n = n + 1;
  12.     }
  13.  
  14.     printf("3の倍数でも5の倍数でもない数の合計は%d\n", t);
  15.     return 0;
  16. }
  17.  
Success #stdin #stdout 0.01s 5292KB
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3の倍数でも5の倍数でもない数の合計は2632
https://ideone.com/fytykA
language:
C (gcc 8.3)
created:
13 days ago
visibility:
public

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