# ------------------- 可修改数字 -------------------
dividend = 190010
start = 590
end = 680
max_results = 10
# ---------------------------------------------------
 
count = 0
found = []
pairs = set()  # 用来防止重复组合
 
# 1. 优先显示整除
for d in range(start, end + 1, 5):
    if count >= max_results:
        break
    if dividend % d == 0:
        print(f"{dividend} ÷ {d} = {dividend // d}")
        print("---")
        count += 1
        found.append(d)
 
# 2. 再显示一位小数
for d in range(start, end + 1, 5):
    if count >= max_results:
        break
    if d in found:
        continue
    if (dividend * 10) % d == 0:
        print(f"{dividend} ÷ {d} = {dividend / d}")
        print("---")
        count += 1
        found.append(d)
 
# 3. 平衡拆分 + 去重（不会出现反过来的重复）
for d in range(start, end + 1, 5):
    if count >= max_results:
        break
    if d in found:
        continue
 
    for d2 in range(start, end + 1, 5):
        if d == d2:
            continue
 
        # ✅ 关键：小的放前面，大的放后面，防止重复
        a, b = sorted((d, d2))
        if (a, b) in pairs:
            continue
 
        best = None
        best_diff = 999999
 
        max_a = int(dividend * 10 / d)
        for a_val in range(1, max_a):
            p1 = d * a_val / 10
            p2 = dividend - p1
            if p2 <= 0:
                continue
 
            if (p2 * 10) % d2 == 0:
                val1 = a_val / 10
                val2 = (p2 * 10) / d2 / 10
                diff = abs(val1 - val2)
 
                if diff < best_diff:
                    best_diff = diff
                    best = (val1, val2, int(p1), int(p2))
 
        if best:
            val1, val2, p1, p2 = best
            print(f"{d}、{d2}")
            print(f"{d}*{val1}={p1}")
            print(f"{d2}*{val2}={p2}")
            print("---")
            pairs.add((a, b))  # 记录这组组合
            count += 1
            break

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