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  1. #include <stdio.h>
  2.  
  3. int main() {
  4.     char process[5][3] = {"P1", "P2", "P3", "P4", "P5"};
  5.     int arrival[5] = {3, 5, 0, 5, 4};
  6.     int burst[5] = {4, 3, 2, 1, 3};
  7.     int waiting[5], turnaround[5];
  8.     int start[5], finish[5];
  9.     int n = 5, i, j, temp;
  10.     float totalWT = 0, totalTAT = 0;
  11.  
  12.     // Sort according to arrival time
  13.     for (i = 0; i < n - 1; i++) {
  14.         for (j = i + 1; j < n; j++) {
  15.             if (arrival[i] > arrival[j]) {
  16.                 temp = arrival[i]; arrival[i] = arrival[j]; arrival[j] = temp;
  17.                 temp = burst[i]; burst[i] = burst[j]; burst[j] = temp;
  18.                 char t[3]; 
  19.                 sprintf(t, "%s", process[i]); 
  20.                 sprintf(process[i], "%s", process[j]); 
  21.                 sprintf(process[j], "%s", t);
  22.             }
  23.         }
  24.     }
  25.  
  26.     int currentTime = 0;
  27.  
  28.     for (i = 0; i < n; i++) {
  29.         if (currentTime < arrival[i])
  30.             currentTime = arrival[i];
  31.  
  32.         start[i] = currentTime;
  33.         finish[i] = start[i] + burst[i];
  34.         turnaround[i] = finish[i] - arrival[i];
  35.         waiting[i] = turnaround[i] - burst[i];
  36.  
  37.         totalWT += waiting[i];
  38.         totalTAT += turnaround[i];
  39.  
  40.         currentTime = finish[i];
  41.     }
  42.  
  43.     printf("\n--- FCFS Scheduling ---\n");
  44.     printf("Process\tAT\tBT\tWT\tTAT\n");
  45.     for (i = 0; i < n; i++) {
  46.         printf("%s\t%d\t%d\t%d\t%d\n",
  47.                process[i], arrival[i], burst[i], waiting[i], turnaround[i]);
  48.     }
  49.  
  50.     printf("\nAverage Waiting Time = %.2f", totalWT / n);
  51.     printf("\nAverage Turnaround Time = %.2f\n", totalTAT / n);
  52.  
  53.     return 0;
  54. }
  55.  
Success #stdin #stdout 0s 5292KB
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stdin
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Standard input is empty
stdout
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--- FCFS Scheduling ---
Process	AT	BT	WT	TAT
P3	0	2	0	2
P1	3	4	0	4
P5	4	3	3	6
P4	5	1	5	6
P2	5	3	6	9

Average Waiting Time = 2.80
Average Turnaround Time = 5.40
https://ideone.com/OnWRZB
language:
C (gcc 8.3)
created:
2 days ago
visibility:
public

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