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  1. #include<stdio.h>
  2.  
  3. double r(float x, int n){
  4. 	return n==0?x: (r(x,n-1)+x/r(x,n-1))/2;
  5. }
  6. int main(int argc, char const *argv[])
  7. {
  8. 	float x;
  9. 	scanf("%f",&x);
  10. 	printf("the square root of %f is: %lf\n",x,r(x,30.0));
  11. 	return 0;
  12. }
Success #stdin #stdout 0.01s 5292KB
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stdin
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Standard input is empty
stdout
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the square root of 0.000000 is: -nan
https://ideone.com/IPcs3U
64
language:
C (clang 8.0)
created:
2 days ago
visibility:
public

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