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  1. #include <stdio.h>
  2.  
  3. int main(void) {
  4.  
  5.  
  6. int n=1,x=1;
  7.  
  8. 	do{
  9. 			x=2*x+1;
  10. 			n++;
  11. 		}while(x<=1000);
  12. printf("n=%dの時x=%dで1000を超える\n",n,x);
  13.  
  14.  
  15.  
  16.  
  17. 	// your code goes here
  18. 	return 0;
  19. }
  20.  
Success #stdin #stdout 0.01s 5316KB
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Standard input is empty
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n=10の時x=1023で1000を超える
https://ideone.com/DaIK1F
language:
C (gcc 8.3)
created:
1 day ago
visibility:
public

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